/* Math functions for i387. Copyright (C) 1995, 1996, 1997 Free Software Foundation, Inc. This file is part of the GNU C Library. Contributed by John C. Bowman , 1995. The GNU C Library is free software; you can redistribute it and/or modify it under the terms of the GNU Lesser General Public License as published by the Free Software Foundation; either version 2.1 of the License, or (at your option) any later version. The GNU C Library is distributed in the hope that it will be useful, but WITHOUT ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser General Public License for more details. You should have received a copy of the GNU Lesser General Public License along with the GNU C Library; if not, write to the Free Software Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301, USA. */ #include /* * FIXME! Is there a better algorithm. like FT_MulDiv * * @implemented */ INT APIENTRY EngMulDiv( INT nMultiplicand, INT nMultiplier, INT nDivisor) { #if SIZEOF_LONG_LONG >= 8 long long ret; if (!nDivisor) return -1; /* We want to deal with a positive divisor to simplify the logic. */ if (nDivisor < 0) { nMultiplicand = - nMultiplicand; nDivisor = -nDivisor; } /* If the result is positive, we "add" to round. else, we subtract to round. */ if ( ( (nMultiplicand < 0) && (nMultiplier < 0) ) || ( (nMultiplicand >= 0) && (nMultiplier >= 0) ) ) ret = (((long long)nMultiplicand * nMultiplier) + (nDivisor/2)) / nDivisor; else ret = (((long long)nMultiplicand * nMultiplier) - (nDivisor/2)) / nDivisor; if ((ret > 2147483647) || (ret < -2147483647)) return -1; return ret; #else if (!nDivisor) return -1; /* We want to deal with a positive divisor to simplify the logic. */ if (nDivisor < 0) { nMultiplicand = - nMultiplicand; nDivisor = -nDivisor; } /* If the result is positive, we "add" to round. else, we subtract to round. */ if ( ( (nMultiplicand < 0) && (nMultiplier < 0) ) || ( (nMultiplicand >= 0) && (nMultiplier >= 0) ) ) return ((nMultiplicand * nMultiplier) + (nDivisor/2)) / nDivisor; return ((nMultiplicand * nMultiplier) - (nDivisor/2)) / nDivisor; #endif }