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[FAST486]

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- Interrupts always clear TF.
- Let at least one instruction happen between #DB's (when TF is set).


svn path=/trunk/; revision=68014
This commit is contained in:
Aleksandar Andrejevic 2015-06-04 14:48:07 +00:00
parent d0d90ef6da
commit 673eb8b36f
2 changed files with 10 additions and 13 deletions
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7
reactos/lib/fast486/common.c
View file

@ -430,8 +430,8 @@ Fast486InterruptInternal(PFAST486_STATE State,
State->InstPtr.LowWord = IdtEntry->Offset;
}
/* Clear TF and NT */
State->Flags.Tf = State->Flags.Nt = FALSE;
/* Clear NT */
State->Flags.Nt = FALSE;
if (OldVm)
{
@ -513,6 +513,9 @@ Fast486InterruptInternal(PFAST486_STATE State,
State->Flags.If = FALSE;
}
/* Clear TF */
State->Flags.Tf = FALSE;
return TRUE;
}

16
reactos/lib/fast486/fast486.c
View file

@ -50,10 +50,13 @@ Fast486ExecutionControl(PFAST486_STATE State, FAST486_EXEC_CMD Command)
UCHAR Opcode;
FAST486_OPCODE_HANDLER_PROC CurrentHandler;
INT ProcedureCallCount = 0;
BOOLEAN Trap;
/* Main execution loop */
do
{
Trap = State->Flags.Tf;
if (!State->Halted)
{
NextInst:
@ -90,19 +93,10 @@ NextInst:
/* Clear the interrupt delay flag */
State->DoNotInterrupt = FALSE;
}
else if (State->Flags.Tf && !State->Halted)
else if (Trap && !State->Halted)
{
/* Perform the interrupt */
Fast486PerformInterrupt(State, 0x01);
/*
* Flags and TF are pushed on stack so we can reset TF now,
* to not break into the INT 0x01 handler.
* After the INT 0x01 handler returns, the flags and therefore
* TF are popped back off the stack and restored, so TF will be
* automatically reset to its previous state.
*/
State->Flags.Tf = FALSE;
Fast486PerformInterrupt(State, FAST486_EXCEPTION_DB);
}
else if (State->Flags.If && State->IntSignaled)
{